Which one of the following has the maximum nu | vedclass

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(A) The number of atoms is calculated using the formula: $	ext{Number of atoms} = \frac{	ext{mass}}{	ext{molar mass}} 	imes N_A 	imes 	ext{atomi

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$1 \ g$ of $Li(s)$ [Atomic mass of $Li = 7$]

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(A) The number of atoms is calculated using the formula: $	ext{Number of atoms} = \frac{	ext{mass}}{	ext{molar mass}} 	imes N_A 	imes 	ext{atomicity}$.$(A)$ For $1 \ g$ of $Li$: $\frac{1}{7} 	imes N_A 	imes 1 \approx 0.143 	imes N_A$.$(B)$ For $1 \ g$ of $Ag$: $\frac{1}{108} 	imes N_A 	imes 1 \approx 0.009 	imes N_A$.$(C)$ For $1 \ g$ of $Mg$: $\frac{1}{24} 	imes N_A 	imes 1 \approx 0.042 	imes N_A$.$(D)$ For $1 \ g$ of $O_2$: $\frac{1}{32} 	imes N_A 	imes 2 = \frac{1}{16} 	imes N_A \approx 0.0625 	imes N_A$.Comparing the values,$1 \ g$ of $Li$ has the maximum number of atoms.

Which one of the following has the maximum number of atoms?

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