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(A) The molar mass of water $(H_2O)$ is $18 \ g/mol$.Given mass of water $= 18 \ mg = 18 	imes 10^{-3} \ g = 0.018 \ g$.Number of moles $= \frac{	ex

Vedclass · Accepted Answer

$N_A 	imes 10^{-3}$

Vedclass · Answer

(A) The molar mass of water $(H_2O)$ is $18 \ g/mol$.Given mass of water $= 18 \ mg = 18 	imes 10^{-3} \ g = 0.018 \ g$.Number of moles $= \frac{	ext{Given mass}}{	ext{Molar mass}} = \frac{0.018 \ g}{18 \ g/mol} = 0.001 \ mol = 10^{-3} \ mol$.Number of molecules $= 	ext{Number of moles} 	imes N_A = 10^{-3} 	imes N_A = N_A 	imes 10^{-3}$.

Calculate the number of molecules in $18 \ mg$ of water in terms of Avogadro's number $(N_A)$.

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