Which one of the following ions has the same | vedclass

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(B) The electronic configuration of vanadium ($V$,$Z=23$) is $[Ar] 3d^3 4s^2$. For $V^{3+}$,the configuration is $[Ar] 3d^2 4s^0$,which contains $2$ u

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$Ni^{2+}$

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(B) The electronic configuration of vanadium ($V$,$Z=23$) is $[Ar] 3d^3 4s^2$. For $V^{3+}$,the configuration is $[Ar] 3d^2 4s^0$,which contains $2$ unpaired electrons. Now,let us check the options: $Fe^{3+}$ $(Z=26)$: $[Ar] 3d^5$,which has $5$ unpaired electrons. $Ni^{2+}$ $(Z=28)$: $[Ar] 3d^8$,which has $2$ unpaired electrons. $Mn^{2+}$ $(Z=25)$: $[Ar] 3d^5$,which has $5$ unpaired electrons. $Cr^{3+}$ $(Z=24)$: $[Ar] 3d^3$,which has $3$ unpaired electrons. Thus,$Ni^{2+}$ has the same number of unpaired electrons as $V^{3+}$.

Which one of the following ions has the same number of unpaired electrons as those present in $V^{3+}$ ion?

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