Which one of the following is correct about t | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The stability of oxidation states in Group $14$ elements is governed by the inert pair effect. As we move down the group from $Si$ to $Pb$,the sta

Vedclass · Accepted Answer

$Pb^{2+} > Pb^{4+}$

Vedclass · Answer

(A) The stability of oxidation states in Group $14$ elements is governed by the inert pair effect. As we move down the group from $Si$ to $Pb$,the stability of the $+2$ oxidation state increases,while the stability of the $+4$ oxidation state decreases. For Lead $(Pb)$,which is at the bottom of the group,the $+2$ oxidation state is significantly more stable than the $+4$ oxidation state due to the inert pair effect. Therefore,$Pb^{2+} > Pb^{4+}$ is the correct order of stability.

Which one of the following is correct about the stability of the given ions?

Similar Questions

The structure of silicates in which three oxygen atoms of $[SiO_4]^{4-}$ are shared is known as:

The last element of group-$14$ is found to be

The element with atomic number $Z = 114$ has been discovered recently. It will belong to which of the following family/group and electronic configuration?

Consider the following reactions:
$PCl_{3} + 3H_{2}O \longrightarrow A + 3HCl$
$A + H_{2}O \longrightarrow B + HCl$
Identify the number of ionisable protons present in the product $B$.

Assertion $(A): [SiF_6]^{2-}$ is formed but $[SiCl_6]^{2-}$ is not.
Reason $(R):$ Electronegativity $(EN)$ of $F$ is higher than $EN$ of $Cl$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module