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(B) $Me_{3}CONa + EtCl \rightarrow Me_{3}COEt + NaCl$Williamson synthesis involves the reaction of an alkoxide with a primary alkyl halide to form an

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Mixing $Me_{3}CONa$ with $EtCl$

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(B) $Me_{3}CONa + EtCl \rightarrow Me_{3}COEt + NaCl$Williamson synthesis involves the reaction of an alkoxide with a primary alkyl halide to form an ether.Since $EtCl$ is a primary $(1^{\circ})$ alkyl halide and $Me_{3}CONa$ is a bulky alkoxide, this reaction proceeds via an $S_{N}2$ mechanism to yield the desired ether.Option $A$ would result in elimination $(E2)$ because $Me_{3}CCl$ is a tertiary alkyl halide.Therefore, the correct option is $B$.

Which one of the following methods is used to prepare $Me_{3}COEt$ with a good yield?

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