Which term of the A.P. -1, 3, 7, 11, ldots is | vedclass

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(B) Given $A.P.$ is $-1, 3, 7, 11, \ldots$Here,the first term $a = -1$.The common difference $d = 3 - (-1) = 3 + 1 = 4$.Let the $n^{th}$ term be $a_n

Vedclass · Accepted Answer

$25$

Vedclass · Answer

(B) Given $A.P.$ is $-1, 3, 7, 11, \ldots$Here,the first term $a = -1$.The common difference $d = 3 - (-1) = 3 + 1 = 4$.Let the $n^{th}$ term be $a_n = 95$.The formula for the $n^{th}$ term of an $A.P.$ is $a_n = a + (n - 1)d$.Substituting the values: $95 = -1 + (n - 1)4$.$95 + 1 = (n - 1)4$.$96 = (n - 1)4$.$n - 1 = 96 / 4 = 24$.$n = 24 + 1 = 25$.Therefore,the $25^{th}$ term of the $A.P.$ is $95$.

Which term of the $A.P.$ $-1, 3, 7, 11, \ldots$ is $95$ (in $^{th}$)?

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