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(B) When white phosphorus $(P_4)$ is heated with concentrated $NaOH$ in an inert atmosphere of $CO_2$,it undergoes disproportionation to form phosphin

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$NaH_2PO_2, H_2SO_4$

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(B) When white phosphorus $(P_4)$ is heated with concentrated $NaOH$ in an inert atmosphere of $CO_2$,it undergoes disproportionation to form phosphine $(PH_3)$ and sodium hypophosphite $(NaH_2PO_2)$.$P_4 + 3NaOH + 3H_2O \rightarrow PH_3(A) + 3NaH_2PO_2(B)$When phosphine $(A)$ is bubbled into aqueous $CuSO_4$ solution,it forms copper phosphide $(Cu_3P_2)$ and sulfuric acid $(H_2SO_4)$.$3CuSO_4 + 2PH_3 \rightarrow Cu_3P_2 + 3H_2SO_4(C)$Therefore,$B$ is $NaH_2PO_2$ and $C$ is $H_2SO_4$.

White phosphorus is heated with concentrated $NaOH$ in $CO_2$ atmosphere to form a gas $A$ and compound $B$. When $A$ is bubbled into aqueous $CuSO_4$ solution,copper phosphide and $C$ are formed. $B$ and $C$ are respectively:

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