Why is BiH_{3} the strongest reducing agent a | vedclass

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(B) As we move down the group from $N$ to $Bi$,the atomic size of the central atom increases.This leads to an increase in the bond length of the $E-H$

Vedclass · Accepted Answer

$BiH_{3}$ has the lowest bond dissociation energy.

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(B) As we move down the group from $N$ to $Bi$,the atomic size of the central atom increases.This leads to an increase in the bond length of the $E-H$ bond (where $E = N, P, As, Sb, Bi$).Consequently,the bond dissociation enthalpy decreases significantly from $NH_{3}$ to $BiH_{3}$.Since $BiH_{3}$ has the lowest bond dissociation energy,it can easily release $H$ atoms,making it the strongest reducing agent among the hydrides of Group $15$ elements.

Why is $BiH_{3}$ the strongest reducing agent amongst all the hydrides of Group $15$ elements?

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