White phosphorus,when heated with conc. NaOH | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) White phosphorus $(P_4)$ undergoes disproportionation reaction when heated with concentrated $NaOH$ solution to form phosphine $(PH_3)$ and sodium

Vedclass · Accepted Answer

$+1$

Vedclass · Answer

(C) White phosphorus $(P_4)$ undergoes disproportionation reaction when heated with concentrated $NaOH$ solution to form phosphine $(PH_3)$ and sodium hypophosphite $(NaH_2PO_2)$.The chemical equation is: $P_4 + 3NaOH + 3H_2O \rightarrow PH_3 + 3NaH_2PO_2$.In the salt $NaH_2PO_2$ (sodium hypophosphite),let the oxidation state of $P$ be $x$.The sum of oxidation states is: $(+1) + 2(+1) + x + 2(-2) = 0$.$1 + 2 + x - 4 = 0$.$x - 1 = 0$.$x = +1$.

White phosphorus,when heated with conc. $NaOH$ solution in an inert atmosphere of $CO_2$,forms phosphine and a sodium salt of oxoacid of phosphorus,$'X'$. The oxidation state of phosphorus in $'X'$ is

Similar Questions

In the Ostwald's process for the manufacture of $HNO_3$,the catalyst used is

Which of the following halides does not exist?

What are the products obtained when ammonia is reacted with excess chlorine?

The correct order of reducing abilities of hydrides of group $15$ elements is:

Explain the nature of hydride compounds of group-$15$ elements. Explain the nature of oxide compounds of group-$15$ elements. Write a note on halide compounds of group-$15$ elements.

Vedclass Test Series

Exam Paper Generator

Online Exam Module