Using the remainder theorem,find the remainde | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) According to the remainder theorem,if a polynomial $p(x)$ is divided by $(x - a)$,the remainder is $p(a)$.Here,the divisor is $x + 4$,which can be

Vedclass · Accepted Answer

$80$

Vedclass · Answer

(A) According to the remainder theorem,if a polynomial $p(x)$ is divided by $(x - a)$,the remainder is $p(a)$.Here,the divisor is $x + 4$,which can be written as $x - (-4)$.Therefore,$a = -4$.Now,substitute $x = -4$ into the polynomial $p(x) = x^3 + x^2 - 26x + 24$:$p(-4) = (-4)^3 + (-4)^2 - 26(-4) + 24$$p(-4) = -64 + 16 + 104 + 24$$p(-4) = -64 + 144$$p(-4) = 80$.Thus,the remainder is $80$.

Using the remainder theorem,find the remainder when the polynomial $p(x) = x^3 + x^2 - 26x + 24$ is divided by the divisor $x + 4$.

Similar Questions

Which one of the following is a polynomial?

Find the quotient and the remainder when $2x^2 - 7x - 15$ is divided by $2x - 3$.

With the help of the remainder theorem,find the remainder when the polynomial $x^{3}+7x^{2}+17x+25$ is divided by $x+4$.

If $x+1$ is a factor of the polynomial $2x^2+kx$,then the value of $k$ is

Find the value of the following polynomial at the indicated value of the variable:
$q(y) = 5y^3 - 4y^2 + 14y - \sqrt{3}$ at $y = 2$

Vedclass Test Series

Exam Paper Generator

Online Exam Module