Class 11MathematicsTrigonometrical EquationsRelation between sides and angles, Solutions of triangles
EasyWith usual notations in $\Delta ABC$,$a=3$,$c=2$ and $\sin C=\frac{2}{3}$,then $\angle A=$
- A$\frac{\pi}{4}$
- B$\frac{\pi}{3}$
- C$\frac{\pi}{2}$
- D$\frac{\pi}{6}$
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In any triangle $ABC$,$AB = 2, BC = 4, CA = 3$ and $D$ is the midpoint of $BC$. Then:
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View SolutionIf in a $\Delta ABC$,$b = 2$,$c = \sqrt{3}$,$\angle A = \frac{\pi}{6}$,then $R = $?
If $(a+b) \cos C + (b+c) \cos A + (c+a) \cos B = 72$ and if $a = 18, b = 24$,then the area of the triangle $ABC$ is
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