Work done in moving a positive charge on an equipotential surface is

  • A
    Finite,positive but not zero
  • B
    Finite,negative but not zero
  • C
    Zero
  • D
    Infinite

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Similar Questions

Assertion: Two equipotential surfaces cannot cut each other.
Reason: Two equipotential surfaces are parallel to each other.

Two charges $2 \; \mu C$ and $-2 \; \mu C$ are placed at points $A$ and $B$ which are $6 \; cm$ apart.
$(a)$ Identify an equipotential surface of the system.
$(b)$ What is the direction of the electric field at every point on this surface?

Electric field is always ...... to the equipotential surface at every point. (Fill in the gap)

Assertion $(A)$: In a region of constant potential,the electric field is zero and there can be no charge inside the region.
Reason $(R)$: According to Gauss's law,the charge inside the region should be zero if the electric field is zero.

In the electric field of a point charge $q$,a certain charge is carried from point $A$ to points $B, C, D$ and $E$ as shown in the figure. Then the work done:

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