Write in ascending order of stability of $1^{\circ}$,$2^{\circ}$ and $3^{\circ}$ carbocations and free radicals.

  • A
    $1^{\circ} < 2^{\circ} < 3^{\circ}$
  • B
    $3^{\circ} < 2^{\circ} < 1^{\circ}$
  • C
    $1^{\circ} = 2^{\circ} = 3^{\circ}$
  • D
    $2^{\circ} < 1^{\circ} < 3^{\circ}$

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Which of the following carbocations is expected to be most stable?

Homolytic fission of the following alkanes forms free radicals: $CH_3-CH_3$,$CH_3-CH_2-CH_3$,$(CH_3)_2CH-CH_3$,and $CH_3-CH_2-CH(CH_3)_2$. The increasing order of stability of the resulting free radicals is:

State True or False for the following statements:
$(i)$ $\mathop{C}\limits^{+}H_3$ and $CH_3\mathop{C}\limits^{+}H_2$ both are primary carbocations.
$(ii)$ $(CH_3)_3\mathop{C}\limits^{+}$ is a tertiary carbocation and all carbons are $sp^3$ hybridized.
$(iii)$ $\mathop{C}\limits^{+}H_3$ is trigonal planar.
$(iv)$ $CH_4$ is not trigonal planar.

The shape of a carbonium ion (carbocation) is:

In the given compound,$Cl$ will be liberated easily in the form of:

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