Write 'True' or 'False' and justify your answer:
The capacity of a cylindrical vessel with a hemispherical portion raised upward at the bottom as shown in the figure is $\frac{\pi r^{2}}{3} [3 h-2 r]$.

Vedclass pdf generator app on play store
Vedclass iOS app on app store
(TRUE) True.
We know that the capacity (volume) of a cylindrical vessel is given by $V_{cylinder} = \pi r^{2} h$.
The capacity (volume) of a hemisphere is given by $V_{hemisphere} = \frac{2}{3} \pi r^{3}$.
From the figure,the hemispherical portion is raised upward at the bottom,which means it occupies space inside the cylinder. Therefore,the capacity of the vessel is the volume of the cylinder minus the volume of the hemisphere.
Capacity of the vessel = $V_{cylinder} - V_{hemisphere}$
$= \pi r^{2} h - \frac{2}{3} \pi r^{3}$
$= \pi r^{2} (h - \frac{2}{3} r)$
$= \frac{\pi r^{2}}{3} (3h - 2r)$.

Explore More

Similar Questions

The base of a cone with radius $0.6 \ m$ and height $1.6 \ m$ is hemispherical. Find the volume of this combined solid in $m^{3}$.

The base of a cone with radius $15\, cm$ and slant height $25\, cm$ is hemispherical. Find the volume of this solid. $(\pi=3.14)$ (in $cm^{3}$)

Three metallic solid cubes whose edges are $3 \, cm$,$4 \, cm$,and $5 \, cm$ are melted and formed into a single cube. Find the edge of the cube so formed (in $cm$).

The curved surface area of a cone with radius $12 \, cm$ and slant height $20 \, cm$ is ....... $\pi \, cm^2$.

The base of a cone with radius $15 \, cm$ and height $20 \, cm$ is hemispherical. Find the total surface area of this article. $(\pi = 3.14)$ (in $cm^2$) (in $.5$)

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo