State whether the following statement is True or False and justify your answer:
The area of $\Delta ABC$ is $8 \, cm^2$ in which $AB = AC = 4 \, cm$ and $\angle A = 90^{\circ}$.

Vedclass pdf generator app on play store
Vedclass iOS app on app store
(TRUE) Given that $\Delta ABC$ is a right-angled triangle with $\angle A = 90^{\circ}$,$AB = 4 \, cm$,and $AC = 4 \, cm$.
The area of a right-angled triangle is given by the formula:
Area $= \frac{1}{2} \times \text{base} \times \text{height}$
Here,we can take $AC$ as the base and $AB$ as the height.
Area $= \frac{1}{2} \times 4 \, cm \times 4 \, cm$
Area $= \frac{1}{2} \times 16 \, cm^2 = 8 \, cm^2$
Since the calculated area is $8 \, cm^2$,the given statement is True.

Explore More

Similar Questions

$A$ plot,in the shape of a quadrilateral $XYZW$,has $XY = 25 \, m$,$YZ = 60 \, m$,$ZW = 33 \, m$,$WX = 34 \, m$,and $XZ = 65 \, m$. Find its area. (in $, m^2$)

If each side of a triangle is doubled,then find the ratio of the area of the new triangle thus formed to the area of the given triangle.

Difficult
View Solution

Write True or False and justify your answer.
The area of the isosceles triangle is $\frac{5}{4} \sqrt{11} \, cm^2$,if the perimeter is $11 \, cm$ and the base is $5 \, cm$.

From a point in the interior of an equilateral triangle,perpendiculars are drawn on the three sides. The lengths of the perpendiculars are $14 \, cm$,$10 \, cm$,and $6 \, cm$. Find the area of the triangle.

Difficult
View Solution

The area of an isosceles triangle having base $2 \, cm$ and the length of one of the equal sides $4 \, cm$ is

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo