Write the unit of the rate constant for the following reactions:
$1.$ Fourth order
$2.$ Third order

Vedclass pdf generator app on play store
Vedclass iOS app on app store
(N/A) The general formula for the unit of the rate constant $(k)$ for a reaction of order $n$ is given by:
Unit of $k = (mol \ L^{-1})^{1-n} \ s^{-1}$
$1.$ For a fourth order reaction $(n = 4)$:
Unit of $k = (mol \ L^{-1})^{1-4} \ s^{-1} = (mol \ L^{-1})^{-3} \ s^{-1} = mol^{-3} \ L^3 \ s^{-1}$
$2.$ For a third order reaction $(n = 3)$:
Unit of $k = (mol \ L^{-1})^{1-3} \ s^{-1} = (mol \ L^{-1})^{-2} \ s^{-1} = mol^{-2} \ L^2 \ s^{-1}$

Explore More

Similar Questions

Which of the following is an elementary reaction?

What is the time taken for the $3^{rd}$ half-life of a second-order decomposition reaction,given that its first half-life is $20 \ s$ (in $s$)?

The given plots represent the variation of the concentration of a reactant $R$ with time for two different reactions $(i)$ and $(ii).$ The respective orders of the reactions are

The diazonium salt decomposes as $C_6H_5N_2^+Cl^- \to C_6H_5Cl + N_2$. At $0 \ ^\circ C$,the evolution of $N_2$ becomes two times faster when the initial concentration of the salt is doubled. Therefore,it is:

$2 \ NO_{(g)} + Cl_{2(g)} \rightleftharpoons 2 \ NOCl_{(g)}$
This reaction was studied at $-10^{\circ} C$ and the following data was obtained:
$Run$ $[NO]_{0}$ $[Cl_{2}]_{0}$ $r_{0}$
$1$ $0.10$ $0.10$ $0.18$
$2$ $0.10$ $0.20$ $0.35$
$3$ $0.20$ $0.20$ $1.40$

$[NO]_{0}$ and $[Cl_{2}]_{0}$ are the initial concentrations and $r_{0}$ is the initial reaction rate.
The overall order of the reaction is ..........
(Round off to the Nearest Integer).

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo