(A) For $n$ resistors each of resistance $R$ connected in parallel,the minimum resistance is given by $R_{\min} = \frac{R}{n}$.Given $R = 1 \ \Omega$

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(A) For $n$ resistors each of resistance $R$ connected in parallel,the minimum resistance is given by $R_{\min} = \frac{R}{n}$.Given $R = 1 \ \Omega$ and $n = 10$,we have $R_{\min} = \frac{1}{10} \ \Omega$.For $n$ resistors connected in series,the maximum resistance is given by $R_{\max} = nR$.Thus,$R_{\max} = 10 \times 1 = 10 \ \Omega$.The ratio of minimum to maximum resistance is $\frac{R_{\min}}{R_{\max}} = \frac{1/10}{10} = \frac{1}{100}$.

Class 12 Physics Current Electricity Equivalent Resistance - Series and Parallel , Circuit

Easy

You are given $10$ resistors each of resistance $1 \ \Omega$. First,they are connected to obtain the possible minimum resistance. Then,they are connected to obtain the possible maximum resistance. The ratio of minimum and maximum resistance is . . . . . . .

GUJCET 2013 All GUJCET

A
$\frac{1}{100}$
B
$\frac{1}{50}$
C
$\frac{1}{1000}$
D
$\frac{1}{10}$

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You are given $10$ resistors each of resistance $1 \ \Omega$. First,they are connected to obtain the possible minimum resistance. Then,they are connected to obtain the possible maximum resistance. The ratio of minimum and maximum resistance is . . . . . . .

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