“By increasing current sensitivity,voltage sensitivity is also increased”. This statement is true or false.

  • A
    True
  • B
    False
  • C
  • D

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Similar Questions

The resistance of a galvanometer is $50\,\Omega$ and it requires $2\,\mu A$ per two division deflection. The value of the shunt required in order to convert this galvanometer into an ammeter of range $5\,A$ is (The number of divisions on the galvanometer scale on one side is $30$).

$A$ galvanometer with a resistance of $12 \,\Omega$ gives full-scale deflection when a current of $3 \, mA$ is passed. It is required to convert it into a voltmeter which can read up to $18 \, V$. The resistance to be connected is ............... $\Omega$.

To verify Ohm's law,a student is provided with a test resistor $R_T$,a high resistance $R_1$,a small resistance $R_2$,two identical galvanometers $G_1$ and $G_2$,and a variable voltage source $V$. The correct circuit to carry out the experiment is

$A$ galvanometer has a $50$ division scale. The battery has no internal resistance. It is found that there is a deflection of $40$ divisions when $R = 2400\,\Omega$. The deflection becomes $20$ divisions when the resistance taken from the resistance box is $4900\,\Omega$. Then we can conclude:

$A$ galvanometer of resistance $50 \Omega$ is connected to a battery of $3 \text{ V}$ along with a resistance of $2950 \Omega$ in series. $A$ full-scale deflection of $30$ divisions is obtained in the galvanometer. In order to reduce this deflection to $20$ divisions,the resistance in series should be: (in $\Omega$)

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