$CH_3CO_2Et + (CH_2)_5(MgBr)_2 \xrightarrow[(2) H^{+}]{(1)} \mathop {C_7H_{14}O}\limits_{(A)}$ ; compound $(A)$ will be

Which one of the following is not formed by aldol condensation of a mixture of ethanal and propanal?

The major product ‘$A$’ in the given reaction is:
$\text{Benzaldehyde} + \text{Acetophenone} \xrightarrow[293 \text{ K}]{OH^-} \text{'A' (Major product)}$

Compound $A$ (molecular formula $C_3H_8O$) is treated with acidified potassium dichromate to form a product $B$ (molecular formula $C_3H_6O$). $B$ forms a shining silver mirror on warming with ammoniacal silver nitrate,and $B$ when treated with an aqueous solution of $NH_2NHCONH_2$ and sodium acetate gives a product $C$. Identify the structure of $C$.

Compound $(A)$ with molecular formula $C_6H_{12}O_3$ gives a positive iodoform test and a negative Tollens' test. Upon hydrolysis with a drop of $H_2SO_4$,it gives a product that shows a positive Tollens' test. Compound $(A)$ is:

Assertion : Benzaldehyde is more reactive than ethanol towards nucleophilic attack.
Reason : The overall effect of $-I$ and $+R$ effect of phenyl group decreases the electron density on the carbon atom of $>C=O$ group in benzaldehyde.