mathop {lim }limits_{x to 3} frac{{sqrt {3x} | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) ધારો કે $A = \mathop {\lim }\limits_{x 	o 3} \frac{{\sqrt {3x} - 3}}{{\sqrt {2x - 4} - \sqrt 2 }}$.અંશ અને છેદનું સંમેયીકરણ કરતા:$A = \mathop {\l

Vedclass · Accepted Answer

$\frac{1}{{\sqrt 2 }}$

Vedclass · Answer

(B) ધારો કે $A = \mathop {\lim }\limits_{x 	o 3} \frac{{\sqrt {3x} - 3}}{{\sqrt {2x - 4} - \sqrt 2 }}$.અંશ અને છેદનું સંમેયીકરણ કરતા:$A = \mathop {\lim }\limits_{x 	o 3} \frac{(\sqrt{3x} - 3)(\sqrt{3x} + 3)(\sqrt{2x - 4} + \sqrt{2})}{(\sqrt{2x - 4} - \sqrt{2})(\sqrt{2x - 4} + \sqrt{2})(\sqrt{3x} + 3)}$$A = \mathop {\lim }\limits_{x 	o 3} \frac{(3x - 9)(\sqrt{2x - 4} + \sqrt{2})}{(2x - 4 - 2)(\sqrt{3x} + 3)}$$A = \mathop {\lim }\limits_{x 	o 3} \frac{3(x - 3)(\sqrt{2x - 4} + \sqrt{2})}{2(x - 3)(\sqrt{3x} + 3)}$$(x - 3)$ ને દૂર કરતા:$A = \frac{3}{2} 	imes \frac{\sqrt{2(3) - 4} + \sqrt{2}}{\sqrt{3(3)} + 3}$$A = \frac{3}{2} 	imes \frac{\sqrt{2} + \sqrt{2}}{3 + 3} = \frac{3}{2} 	imes \frac{2\sqrt{2}}{6} = \frac{1}{\sqrt{2}}$.

$\mathop {\lim }\limits_{x \to 3} \frac{{\sqrt {3x} - 3}}{{\sqrt {2x - 4} - \sqrt 2 }}$ ની કિંમત શોધો.

Similar Questions

$\lim _{x \rightarrow 2}\left(\frac{5^x+5^{3-x}-30}{5^{3-x}-5^{\frac{x}{2}}}\right)=$

$\lim_{x \rightarrow -2^{+}} ([x]^2 - [x] - 2) + \lim_{x \rightarrow -3^{-}} ([x]^2 - 4[x] + 3) =$

$\lim _{n \rightarrow \infty} \frac{1+2+3+\ldots+n}{n^{2}}$ ની કિંમત શું છે?

જો $f(x) = \frac{e^{1/x} - 1}{e^{1/x} + 1}$ હોય,તો

$\lim _{n \rightarrow \infty} n \sin \frac{2 \pi}{3 n} \cos \frac{2 \pi}{3 n}$ ની કિંમત શોધો.

Vedclass Test Series

Exam Paper Generator

Online Exam Module