Which of the following is the correct increasing order of $O-O$ bond length in $O_2$,$O_3$,and $H_2O_2$?
- A$H_2O_2 < O_3 < O_2$
- B$O_2 < O_3 < H_2O_2$
- C$O_3 < O_2 < H_2O_2$
- D$O_2 < H_2O_2 < O_3$
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Similar Questions
$CO$ has the same number of electrons as which of the following ions? Or,which ion is isoelectronic with $CO$?
MediumIIT 1982
View SolutionMatch the following species in List-$I$ with the number of lone pairs in List-$II$.
List-$I$ (Species) List-$II$ (Number of lone pairs) $A. \ CH_3COCH_3$ $I. \ 2$ $B. \ CH_3CO^+$ $II. \ 0$ $C. \ CH_3CH_2^+$ $III. \ 1$ $IV. \ 3$
| List-$I$ (Species) | List-$II$ (Number of lone pairs) |
|---|---|
| $A. \ CH_3COCH_3$ | $I. \ 2$ |
| $B. \ CH_3CO^+$ | $II. \ 0$ |
| $C. \ CH_3CH_2^+$ | $III. \ 1$ |
| $IV. \ 3$ |
Consider the following compounds:
$I. H_3X-NCS$
$II. H_3Y-NCS$
$III. (H_3X)_2O$
$IV. (H_3Y)_2O$
The incorrect statement regarding the given compounds is:
$I. H_3X-NCS$
$II. H_3Y-NCS$
$III. (H_3X)_2O$
$IV. (H_3Y)_2O$
The incorrect statement regarding the given compounds is:
$P_4O_{10}$ has short and long $P-O$ bonds. The number of short $(P=O)$ bonds in this compound is:
Easy
View SolutionDraw Lewis structures of the following molecules and ions: $H_2S$,$SiCl_4$,$BeF_2$,$CO_3^{2-}$,$HCOOH$.
Difficult
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