CH_3CH_2CONH_2 xrightarrow{Br_2 / KOH_{(aq)}} | vedclass

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(D) In the given reaction sequence:$1.$ $CH_3CH_2CONH_2 \xrightarrow{Br_2 / KOH} CH_3CH_2NH_2 (X)$. This is the Hofmann bromamide degradation reaction

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(D) In the given reaction sequence:$1.$ $CH_3CH_2CONH_2 \xrightarrow{Br_2 / KOH} CH_3CH_2NH_2 (X)$. This is the Hofmann bromamide degradation reaction,where an amide is converted to a primary amine with one less carbon atom.$2.$ $CH_3CH_2NH_2 (X) \xrightarrow{C_6H_5COCl} C_6H_5CONHCH_2CH_3 (Y)$. The reaction of an amine with an acid chloride (like benzoyl chloride) in the presence of a base is known as the Schotten-Baumann reaction.$3.$ $X$ (Ethylamine) is an aliphatic amine,while $Y$ ($N$-ethylbenzamide) is an amide. Amines are much more basic than amides because the lone pair of electrons on the nitrogen atom in an amide is delocalized through resonance with the carbonyl group $(C=O)$.Therefore,all the given statements are correct.

List-$I$ (Mixture of Compounds)	List-$II$ (Reagent used to distinguish)
$A$. Diethyl amine + Ethyl amine	$I$. Bromine water
$B$. Acetaldehyde + Acetone	$II$. $CHCl_3 + KOH, \Delta$
$C$. Ethanol + Phenol	$III$. Neutral $FeCl_3$
$D$. Benzoic acid + Cinnamic acid	$IV$. Ammonical silver nitrate

$CH_3CH_2CONH_2$ $\xrightarrow{Br_2 / KOH_{(aq)}} X$ $\xrightarrow{C_6H_5COCl} Y$. Which statement is true?

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