What is the number of optically active isomer | vedclass

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(D) The molecular formula $C_7H_{16}$ corresponds to an alkane $(C_nH_{2n+2})$. To find optically active isomers,we look for chiral centers in the bra

Vedclass · Accepted Answer

$6$

Vedclass · Answer

(D) The molecular formula $C_7H_{16}$ corresponds to an alkane $(C_nH_{2n+2})$. To find optically active isomers,we look for chiral centers in the branched isomers of heptane. The isomers of heptane are: $1$. $n$-Heptane (achiral) $2$. $2$-Methylhexane: $CH_3-CH(CH_3)-CH_2-CH_2-CH_2-CH_3$. The $C_2$ carbon is chiral. It has $2$ enantiomers. $3$. $3$-Methylhexane: $CH_3-CH_2-CH(CH_3)-CH_2-CH_2-CH_3$. The $C_3$ carbon is chiral. It has $2$ enantiomers. $4$. $3$-Ethylpentane (achiral) $5$. $2,2$-Dimethylpentane (achiral) $6$. $2,3$-Dimethylpentane: $CH_3-CH(CH_3)-CH(CH_3)-CH_2-CH_3$. The $C_3$ carbon is chiral. It has $2$ enantiomers. $7$. $2,4$-Dimethylpentane (achiral) $8$. $3,3$-Dimethylpentane (achiral) $9$. $2,2,3$-Trimethylbutane (achiral) Total optically active isomers = $2$ (from $2$-methylhexane) + $2$ (from $3$-methylhexane) + $2$ (from $2,3$-dimethylpentane) = $6$.

What is the number of optically active isomers for the compound with the molecular formula $C_7H_{16}$?

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