The oxidation state of Fe in Na_2[Fe(CN)_5NO] | vedclass

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Question

(A) In the complex $Na_2[Fe(CN)_5NO]$,the oxidation state of $Fe$ is calculated as follows:Let the oxidation state of $Fe$ be $x$.The oxidation state

Vedclass · Accepted Answer

$+2$

Vedclass · Answer

(A) In the complex $Na_2[Fe(CN)_5NO]$,the oxidation state of $Fe$ is calculated as follows:Let the oxidation state of $Fe$ be $x$.The oxidation state of $Na$ is $+1$,$CN$ is $-1$,and $NO$ (nitrosonium ligand) is $+1$.$2(+1) + x + 5(-1) + 1 = 0$$2 + x - 5 + 1 = 0$$x - 2 = 0$$x = +2$Therefore,the oxidation state of $Fe$ is $+2$.

The oxidation state of $Fe$ in $Na_2[Fe(CN)_5NO]$ is .......

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