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(A) $(i)$ Hydroboration-oxidation of propene yields propan$-1-$ol.$(ii)$ Hydration of propene in the presence of dilute sulfuric acid yields propan$-2

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Propan$-1-$ol and Propan$-2-$ol

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(A) $(i)$ Hydroboration-oxidation of propene yields propan$-1-$ol.$(ii)$ Hydration of propene in the presence of dilute sulfuric acid yields propan$-2-$ol.In the hydroboration-oxidation process,diborane adds to the alkene following anti-Markovnikov's rule to form a trialkylborane,which upon oxidation with $H_2O_2$ in an alkaline medium gives propan$-1-$ol.Conversely,the acid-catalyzed hydration of propene follows Markovnikov's rule,where the hydroxyl group attaches to the more substituted carbon,resulting in propan$-2-$ol.

What are the products obtained from the hydroboration-oxidation of propene and its hydration in the presence of dilute sulfuric acid,respectively?

Similar Questions

What is meant by hydroboration-oxidation reaction? Illustrate it with an example.

What product is formed when the alkene $R-CH=CH_2$ reacts with $B_2H_6$ in the presence of $H_2O_2$?

$CH_2 = CH_2 + B_2H_6 \xrightarrow[H_2O_2]{NaOH} \text{Product}$.
The product in the above reaction is:

For the given reaction:
(Cyclohexyl)-$CH$=$CH$-(Cyclohexyl) $\xrightarrow{KMnO_4/H^+}$ '$P$' (major product)
'$P$' is:

$CH_2=CHCl$ reacts with $HCl$ to form

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