A and B, working separately,can complete a pi | vedclass

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(B) Work done by $A$ in $1$ day $= \frac{1}{9}$.Work done by $B$ in $1$ day $= \frac{1}{12}$.Work done by $(A+B)$ in $2$ days (one pair) $= \frac{1}{9

Vedclass · Accepted Answer

$10 \frac{1}{4}$

Vedclass · Answer

(B) Work done by $A$ in $1$ day $= \frac{1}{9}$.Work done by $B$ in $1$ day $= \frac{1}{12}$.Work done by $(A+B)$ in $2$ days (one pair) $= \frac{1}{9} + \frac{1}{12} = \frac{4+3}{36} = \frac{7}{36}$.In $5$ pairs of days ($10$ days),work done $= 5 	imes \frac{7}{36} = \frac{35}{36}$.Remaining work $= 1 - \frac{35}{36} = \frac{1}{36}$.On the $11^{th}$ day,it is $A$'s turn. $A$ completes $\frac{1}{9}$ work in $1$ day.Time taken by $A$ to complete $\frac{1}{36}$ work $= \frac{1/36}{1/9} = \frac{9}{36} = \frac{1}{4}$ day.Total time $= 10 + \frac{1}{4} = 10 \frac{1}{4}$ days.

$A$ and $B,$ working separately,can complete a piece of work in $9$ and $12$ days,respectively. If they work for a day alternately,$A$ beginning,in how many days will the work be completed?

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