$15 \frac{2}{3} \times 3 \frac{1}{6} + 6 \frac{1}{3} = 11 \frac{7}{18} + ?$

  • A
    $39 \frac{5}{9}$
  • B
    $137 \frac{4}{9}$
  • C
    $26 \frac{7}{9}$
  • D
    $44 \frac{5}{9}$

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