If the mother has a genotype of Hb^{A}Hb^{S} | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) Sickle cell anemia is an autosomal recessive disorder.Both parents are carriers $(Hb^{A}Hb^{S} 	imes Hb^{A}Hb^{S})$.The Punnett square for this c

Vedclass · Accepted Answer

$12.5$

Vedclass · Answer

(D) Sickle cell anemia is an autosomal recessive disorder.Both parents are carriers $(Hb^{A}Hb^{S} 	imes Hb^{A}Hb^{S})$.The Punnett square for this cross results in:- $Hb^{A}Hb^{A}$ (Normal): $25 \%$- $Hb^{A}Hb^{S}$ (Carrier): $50 \%$- $Hb^{S}Hb^{S}$ (Affected): $25 \%$The probability of having an affected child $(Hb^{S}Hb^{S})$ is $1/4$ or $25 \%$.Since the question asks for the probability of having an affected son,we must consider the probability of the child being male $(1/2)$ and the probability of the child being affected $(1/4)$.Probability = $P(	ext{Affected}) 	imes P(	ext{Male}) = 1/4 	imes 1/2 = 1/8$ or $12.5 \%$.

If the mother has a genotype of $Hb^{A}Hb^{S}$ and the father has a genotype of $Hb^{A}Hb^{S}$,what is the probability of having an affected son (in $\%$)?

Similar Questions

One of the genes present exclusively on the $X$-chromosome in humans is concerned with

Among symbols $A, B$ and $C$,what does $C$ indicate?

Colour blindness is caused by a single

Polydactyly in humans is caused by a/an:

In Huntington's disease,the unaffected persons are homozygous for normal allele $h$. The following pedigree is erroneous because:

Vedclass Test Series

Exam Paper Generator

Online Exam Module