If a population is in Hardy-Weinberg equilibrium and $25\%$ of the individuals exhibit the recessive trait,find the frequency of the recessive allele in the gene pool.
- A$0.5$
- B$0.25$
- C$0.20$
- D$0.75$
Explore More
Similar Questions
Explain the Hardy-Weinberg principle using an algebraic equation.
Medium
View SolutionIn a population,the frequency of the $M$ allele is $0.8$. Calculate the frequency of the homozygous recessive genotype in that population. (in $\%$)
In a randomly mating population of $28,800$ individuals,the percentage of dominant homozygous individuals is $49\%$. Find the percentage of heterozygous individuals. (in $\%$)
Medium
View SolutionIn a population exhibiting random mating,the frequency of a disease-causing recessive allele is $80\%$. What will be the frequency of carrier individuals in the population (in $\%$)?
Medium
View SolutionAt a particular locus,the frequency of the $A$ allele is $0.6$ and that of the $a$ allele is $0.4$. What would be the frequency of heterozygotes in a random mating population at equilibrium?
MediumAIPMT 2005
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo