Delta XYZ sim Delta DEF for the correspondenc | vedclass

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(C) Given that $\Delta XYZ \sim \Delta DEF$ under the correspondence $XYZ \leftrightarrow DEF$.This implies that the corresponding angles are equal: $

Vedclass · Accepted Answer

$55$

Vedclass · Answer

(C) Given that $\Delta XYZ \sim \Delta DEF$ under the correspondence $XYZ \leftrightarrow DEF$.This implies that the corresponding angles are equal: $\angle X = \angle D$,$\angle Y = \angle E$,and $\angle Z = \angle F$.In $\Delta XYZ$,the sum of the angles is $180^{\circ}$.Therefore,$m \angle X + m \angle Y + m \angle Z = 180^{\circ}$.Substituting the given values: $50^{\circ} + 75^{\circ} + m \angle Z = 180^{\circ}$.$125^{\circ} + m \angle Z = 180^{\circ}$.$m \angle Z = 180^{\circ} - 125^{\circ} = 55^{\circ}$.Since $\angle Z = \angle F$,we have $m \angle F = 55^{\circ}$.

$\Delta XYZ \sim \Delta DEF$ for the correspondence $XYZ \leftrightarrow DEF$. If $m \angle X = 50^{\circ}$ and $m \angle Y = 75^{\circ}$,then $m \angle F = \dots$ (in $^{\circ}$)

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