If sin ^{2}(3 x+30^{circ})+cos ^{2}(2 x+45^{c | vedclass

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(B) Given the equation $\sin ^{2}(3 x+30^{\circ})+\cos ^{2}(2 x+45^{\circ})=1$.We know the fundamental trigonometric identity $\sin ^{2} 	heta+\cos ^

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(B) Given the equation $\sin ^{2}(3 x+30^{\circ})+\cos ^{2}(2 x+45^{\circ})=1$.We know the fundamental trigonometric identity $\sin ^{2} 	heta+\cos ^{2} 	heta=1$.Comparing the given equation with the identity,we have $3 x+30^{\circ} = 2 x+45^{\circ}$.Subtracting $2x$ from both sides,we get $x+30^{\circ} = 45^{\circ}$.Subtracting $30^{\circ}$ from both sides,we get $x = 15^{\circ}$.

If $\sin ^{2}(3 x+30^{\circ})+\cos ^{2}(2 x+45^{\circ})=1$,then $x = \dots$ (in $^{\circ}$)

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