116 g of a substance upon dissociation react | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) Calculate the moles of each element present in $116 \ g$ of the substance:Moles of $H = \frac{7.5 \ g}{1 \ g/mol} = 7.5 \ mol$Moles of $O = \frac{

Vedclass · Accepted Answer

$2$

Vedclass · Answer

(C) Calculate the moles of each element present in $116 \ g$ of the substance:Moles of $H = \frac{7.5 \ g}{1 \ g/mol} = 7.5 \ mol$Moles of $O = \frac{60 \ g}{16 \ g/mol} = 3.75 \ mol$Moles of $C = \frac{48.5 \ g}{12 \ g/mol} \approx 4.04 \ mol$Dividing by the smallest value $(3.75)$:$H: \frac{7.5}{3.75} = 2$$O: \frac{3.75}{3.75} = 1$$C: \frac{4.04}{3.75} \approx 1.08 \approx 1$The empirical formula is $CH_2O$.Now,check the given options for the empirical formula $CH_2O$:$(A)$ $CH_3COOH$ is $C_2H_4O_2$,which simplifies to $CH_2O$.$(B)$ $HCHO$ is $CH_2O$,which simplifies to $CH_2O$.$(C)$ $CH_3OOCH_3$ is $C_2H_6O_2$,which does not simplify to $CH_2O$.$(D)$ $CH_3CHO$ is $C_2H_4O$,which does not simplify to $CH_2O$.Thus,$2$ formulae ($A$ and $B$) agree with the empirical formula $CH_2O$.

Similar Questions

One mole of one of the sodium salts listed below,having carbon content close to $14.3 \%$,produces $1 \ mole$ of carbon dioxide upon heating (atomic mass of $Na = 23, H = 1, C = 12, O = 16$). The salt is:

Hemoglobin contains $0.334 \% \, Fe$ by weight. If the molecular mass of hemoglobin is approximately $67200 \, g/mol$,determine the number of iron atoms in one molecule of hemoglobin. (Atomic mass of $Fe = 56 \, g/mol$)

$A$ protein $'A'$ contains $0.30\, \%$ of glycine (molecular weight $75$). The minimum molar mass of the protein $'A'$ is $.......\, \times 10^{3} \, g\, mol^{-1}$ [nearest integer]

The molar mass of caffeine is $194$. It contains $28.9\%$ of nitrogen by mass. The number of nitrogen atoms in one molecule of caffeine is:

Define empirical formula and molecular formula.

Vedclass Test Series

Exam Paper Generator

Online Exam Module