How many ATP and NADPH molecules are required | vedclass

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(D) The Calvin cycle consists of three main stages: carboxylation,reduction,and regeneration.To produce one molecule of glucose $(C_6H_{12}O_6)$,the c

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$12 \, NADPH$ and $12 \, ATP$

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(D) The Calvin cycle consists of three main stages: carboxylation,reduction,and regeneration.To produce one molecule of glucose $(C_6H_{12}O_6)$,the cycle must turn $6$ times because each turn fixes one molecule of $CO_2$.In the reduction phase,for every $CO_2$ molecule fixed,$2 \, ATP$ are used for phosphorylation and $2 \, NADPH$ are used for reduction.Since $6$ turns are required for one glucose molecule,the total requirement for the reduction phase is $6 	imes 2 = 12 \, ATP$ and $6 	imes 2 = 12 \, NADPH$.

How many $ATP$ and $NADPH$ molecules are required for the reduction step in the Calvin cycle to produce one molecule of glucose?

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