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(A) Colorblindness is an $X$-linked recessive disorder.Let $X^c$ be the allele for colorblindness and $X$ be the normal allele.The genotype of a color

Vedclass · Accepted Answer

$100\, \%$ sons colorblind and $0\, \%$ daughters colorblind

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(A) Colorblindness is an $X$-linked recessive disorder.Let $X^c$ be the allele for colorblindness and $X$ be the normal allele.The genotype of a colorblind woman is $X^c X^c$.The genotype of a normal man is $XY$.Cross: $X^c X^c 	imes XY$.Offspring genotypes: $X^c X$ (carrier daughter) and $X^c Y$ (colorblind son).Therefore,all sons $(100\, \%)$ will be colorblind,and all daughters $(100\, \%)$ will be carriers (normal phenotype,$0\, \%$ colorblind).Thus,the correct option is $A$.

Choose the correct option for the offspring of a colorblind woman and a normal man.

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