A xrightarrow[text{(ii) } H_3O^{+}]{text{(i) | vedclass

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Question

(A) $1$. Molar mass of $A$ is $121 \ g/mol$. Benzamide $(C_6H_5CONH_2)$ has a molar mass of $121 \ g/mol$ and contains nitrogen,thus giving a positive

Vedclass · Accepted Answer

$A$ = Benzamide,$B$ = Benzoic acid,$C$ = Ethyl benzoate

Vedclass · Answer

(A) $1$. Molar mass of $A$ is $121 \ g/mol$. Benzamide $(C_6H_5CONH_2)$ has a molar mass of $121 \ g/mol$ and contains nitrogen,thus giving a positive Lassaigne's test.$2$. The reaction of benzamide with $NaOH$ followed by $H_3O^+$ is an alkaline hydrolysis,which converts the amide group $(-CONH_2)$ into a carboxylic acid group $(-COOH)$,yielding benzoic acid $(B)$.$3$. Benzoic acid $(B)$ reacts with $NaHCO_3$ to release $CO_2$ gas,causing effervescence.$4$. The reaction of benzoic acid $(B)$ with ethanol $(EtOH)$ in the presence of $H_2SO_4$ and heat is an esterification reaction,which produces ethyl benzoate $(C)$,characterized by a fruity smell.

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The acidity of compounds $I-IV$ in water follows the order:
$I.$ ethanol
$II.$ acetic acid
$III.$ phenol
$IV.$ acetonitrile

The conversion of $CH_{3}CH_{2}COOH$ to the product shown below can be accomplished by:
$CH_{3}CH_{2}CH(OCH_{2}CH_{2}O)$

The product $D$ of the reaction is:
$CH_3Cl$ $\xrightarrow{KCN} (A)$ $\xrightarrow{H_2O} (B)$ $\xrightarrow{NH_3} (C)$ $\xrightarrow{\Delta} (D)$

The product $(A)$ will be:

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