$A$ conductivity cell containing $5 \times 10^{-4} \ M \ NaCl$ solution develops a resistance of $14000 \ \Omega$ at $25^{\circ} C$. Calculate the conductivity of the solution if the cell constant is $0.84 \ cm^{-1}$.
- A$6.0 \times 10^{-5} \ \Omega^{-1} \ cm^{-1}$
- B$3.0 \times 10^{-5} \ \Omega^{-1} \ cm^{-1}$
- C$9.0 \times 10^{-5} \ \Omega^{-1} \ cm^{-1}$
- D$12.0 \times 10^{-5} \ \Omega^{-1} \ cm^{-1}$
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