$\tan ^{-1} x + \tan ^{-1} y = c$ is the general solution of the differential equation:
- A$\frac{dy}{dx} = -\left(\frac{1+y^2}{1+x^2}\right)$
- B$\frac{dy}{dx} = \left(\frac{1+y^2}{1+x^2}\right)$
- C$\frac{dy}{dx} = -\left(\frac{1+x^2}{1+y^2}\right)$
- D$\frac{dy}{dx} = \left(\frac{1+x^2}{1+y^2}\right)$
Explore More
Similar Questions
The differential equation of the family of ellipses $\frac{x^2}{a^2} + \frac{y^2}{b^2} = c$ is given by $\left( y' = \frac{dy}{dx}, y'' = \frac{d^2y}{dx^2} \right)$.
If $l$ and $m$ are the order and degree of the differential equation of all straight lines at a constant distance of $P$ units from the origin,then $l m^2+l^2 m=$
The differential equation whose solution is $y = c_{1} \cos(ax) + c_{2} \sin(ax)$ (where $c_{1}$ and $c_{2}$ are arbitrary constants) is
The differential equation of all circles having center on the $x$-axis and touching the $y$-axis at the origin is:
Verify that the given function $xy = \log y + C$ is a solution of the differential equation $y' = \frac{y^2}{1 - xy}$ $(xy \neq 1)$.
Easy
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo