$1 - x + \frac{x^2}{2!} - \frac{x^3}{3!} + \dots \infty = $

  • A
    $e^x$
  • B
    $e^{-x}$
  • C
    $e$
  • D
    $e^{x^2}$

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Similar Questions

मान लीजिए $C(\theta) = \sum_{n=0}^{\infty} \frac{\cos(n\theta)}{n!}$. निम्नलिखित में से कौन सा कथन असत्य है?

$\frac{1}{2} + \frac{1}{4} + \frac{1}{8 \times 2!} + \frac{1}{16 \times 3!} + \frac{1}{32 \times 4!} + \dots \infty = $

${\left[ {1 + \frac{1}{{2!}} + \frac{1}{{4!}} + \dots \infty } \right]^2} - {\left[ {1 + \frac{1}{{3!}} + \frac{1}{{5!}} + \dots \infty } \right]^2} = $

श्रेणी $\frac{2}{1!} + \frac{6}{2!} + \frac{12}{3!} + \frac{20}{4!} + \dots$ का योग क्या है?

मान लीजिए $\sum_{n=0}^{\infty} \frac{n^3((2n)!) + (2n-1)(n!)}{(n!)((2n)!)} = ae + \frac{b}{e} + c$,जहाँ $a, b, c \in \mathbb{Z}$ और $e = \sum_{n=0}^{\infty} \frac{1}{n!}$ है। तो $a^2 - b + c$ का मान $................$ है।

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