A water film is formed between two parallel w | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The length of the wire is $l = 10 	ext{ cm} = 0.1 	ext{ m}$.The initial distance between the wires is $d_1 = 0.5 	ext{ cm} = 0.005 	ext{ m}$.T

Vedclass · Accepted Answer

$1.44 	imes 10^{-5} 	ext{ J}$

Vedclass · Answer

(C) The length of the wire is $l = 10 	ext{ cm} = 0.1 	ext{ m}$.The initial distance between the wires is $d_1 = 0.5 	ext{ cm} = 0.005 	ext{ m}$.The increase in distance is $\Delta d = 1 	ext{ mm} = 0.001 	ext{ m}$.$A$ water film has two surfaces,so the change in area is $\Delta A = 2 	imes (l 	imes \Delta d)$.$\Delta A = 2 	imes (0.1 	ext{ m} 	imes 0.001 	ext{ m}) = 2 	imes 10^{-4} 	ext{ m}^2$.The surface tension of water is $T = 72 	ext{ mN/m} = 72 	imes 10^{-3} 	ext{ N/m}$.The work done is $W = T 	imes \Delta A$.$W = (72 	imes 10^{-3} 	ext{ N/m}) 	imes (2 	imes 10^{-4} 	ext{ m}^2) = 144 	imes 10^{-7} 	ext{ J} = 1.44 	imes 10^{-5} 	ext{ J}$.

$A$ water film is formed between two parallel wires of $10 \text{ cm}$ length. The distance of $0.5 \text{ cm}$ between the wires is increased by $1 \text{ mm}$. The work done in the process is (surface tension of water $= 72 \text{ mN/m}$).

Similar Questions

The work done in blowing a soap bubble of radius $0.2\, m$ is (the surface tension of soap solution being $0.06\, N/m$).

In an isothermal process,$2$ water drops of radius $1 \, mm$ are combined to form a bigger drop. Find the energy change (in $\mu J$) in this process if the surface tension $T = 0.1 \, N/m$.

The amount of energy required to form a soap bubble of radius $2\,cm$ from a soap solution is nearly $..........\,\times 10^{-4}\,J$: (surface tension of soap solution $=0.03\,N\,m^{-1}$)

One thousand small water drops of equal radii combine to form a big drop. The ratio of final surface energy to the total initial surface energy is

The radius $R$ of the soap bubble is doubled under isothermal conditions. If $T$ is the surface tension of the soap bubble, the work done in doing so is given by (in $\pi R^2 T$)

Vedclass Test Series

Exam Paper Generator

Online Exam Module