$A$ particle of mass $5 \,g$ is executing $S.H.M.$ with an amplitude $0.3 \,m$ and period $\frac{\pi}{5} \,s$. The maximum value of the force acting on the particle is (in $\,N$)

For a particle in $SHM$,if the amplitude of the displacement is $a$ and the amplitude of velocity is $v$,the amplitude of acceleration is

The oscillation of a body on a smooth horizontal surface is represented by the equation $x = A \cos \omega t$,where $x$ is the displacement at time $t$ and $\omega$ is the angular frequency of oscillation. Which one of the following graphs correctly shows the variation of acceleration $a$ with time $t$?

The acceleration of a particle executing $SHM$ is

$A$ body of mass $0.4 \text{ kg}$ performs simple harmonic motion. It experiences a restoring force of $0.4 \text{ N}$ when its displacement from the mean position is $4 \text{ cm}$. The force constant and magnitude of acceleration respectively are

$A$ point mass oscillates along the $x$-axis according to $x = x_0 \sin \left(\omega t - \frac{\pi}{6}\right)$. If the acceleration of the point mass is written as $a = A \sin (\omega t + \delta)$,then: