The acceleration of a particle executing SHM | vedclass

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(C) The acceleration of a particle executing $SHM$ is given by the formula:$\alpha = -\omega^2 y$where $\alpha$ is the acceleration,$\omega$ is the an

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maximum at the extreme position

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(C) The acceleration of a particle executing $SHM$ is given by the formula:$\alpha = -\omega^2 y$where $\alpha$ is the acceleration,$\omega$ is the angular frequency,and $y$ is the displacement from the mean position.From the relation $\alpha \propto y$,it is clear that the magnitude of acceleration is directly proportional to the displacement from the equilibrium position.The maximum displacement of the particle from the mean position is equal to the amplitude $A$.Therefore,the acceleration is maximum when the displacement $y$ is maximum (i.e.,at the extreme positions where $y = \pm A$).

The acceleration of a particle executing $SHM$ is

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