1-chlorobutane on treatment with alcoholic po | vedclass

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Question

(B) Alcoholic $KOH$ acts as a dehydrohalogenating agent. It removes a molecule of $HCl$ from the alkyl halide to form an alkene.For $1-$chlorobutane,t

Vedclass · Accepted Answer

$1-$butene

Vedclass · Answer

(B) Alcoholic $KOH$ acts as a dehydrohalogenating agent. It removes a molecule of $HCl$ from the alkyl halide to form an alkene.For $1-$chlorobutane,the reaction is:$CH_3CH_2CH_2CH_2Cl \xrightarrow{	ext{Alc. } KOH} CH_3CH_2CH=CH_2 + KCl + H_2O$This process is known as dehydrohalogenation,and the major product formed is $1-$butene.Therefore,option $(B)$ is correct.

$1-$chlorobutane on treatment with alcoholic potash forms

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