A(-1, 1) and B(5, 3) are opposite vertices of | vedclass

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(C) Let the vertices of the square be $A(-1, 1)$ and $B(5, 3)$.Since $A$ and $B$ are opposite vertices,the midpoint of $AB$ is $M = (\frac{-1+5}{2}, \

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$3x + y - 8 = 0$

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(C) Let the vertices of the square be $A(-1, 1)$ and $B(5, 3)$.Since $A$ and $B$ are opposite vertices,the midpoint of $AB$ is $M = (\frac{-1+5}{2}, \frac{1+3}{2}) = (2, 2)$.The slope of diagonal $AB$ is $m_{AB} = \frac{3-1}{5-(-1)} = \frac{2}{6} = \frac{1}{3}$.The other diagonal of a square is the perpendicular bisector of the diagonal $AB$.Therefore,the slope of the other diagonal is $m = -\frac{1}{m_{AB}} = -3$.The equation of the other diagonal passing through $M(2, 2)$ with slope $-3$ is:$y - 2 = -3(x - 2)$$y - 2 = -3x + 6$$3x + y - 8 = 0$.

$A(-1, 1)$ and $B(5, 3)$ are opposite vertices of a square in the $xy$-plane. The equation of the other diagonal (not passing through $A$ and $B$) of the square is given by:

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