$\int \tan ^{-1}\left(1-x+x^2\right) d x+\int \tan ^{-1}(x) d x+\int \tan ^{-1}(1-x) d x=$

  • A
    $\frac{\pi}{2} x+C$
  • B
    $\frac{\pi}{4} x+C$
  • C
    $x+C$
  • D
    $\pi x+C$

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