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(B) The person suffers from myopia (nearsightedness) because they cannot see objects beyond $400 \ cm$. To correct this, we need a lens that forms an

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Concave, $-0.25 \ D$

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(B) The person suffers from myopia (nearsightedness) because they cannot see objects beyond $400 \ cm$. To correct this, we need a lens that forms an image at the far point $(v = -400 \ cm)$ for an object placed at infinity $(u = -\infty)$.Using the lens formula: $\frac{1}{f} = \frac{1}{v} - \frac{1}{u}$.Substituting the values: $\frac{1}{f} = \frac{1}{-400} - \frac{1}{-\infty} = \frac{1}{-400} - 0$.Therefore, $f = -400 \ cm = -4 \ m$.The power of the lens is $P = \frac{1}{f(	ext{in } m)} = \frac{1}{-4} = -0.25 \ D$.$A$ negative power indicates a concave lens.

$A$ person can see objects clearly when they lie between $40 \ cm$ and $400 \ cm$ from his eye. In order to increase the maximum distance of distant vision to infinity, the type of lens and power of the correction lens required respectively are

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