$A$ primary alcohol was reacted with pyridinium chlorochromate $(PCC)$,which resulted in a product $P$. The product $P$ on treatment with ammoniacal silver nitrate solution produces:
- AAnhydride of carboxylic acid
- BAldehyde
- CAmide
- DCarboxylate anion
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Similar Questions
The reactant $(A)$ will be:
Difficult
View SolutionThe reaction sequence is as follows:
$Cyclopentanecarboxamide$ $\xrightarrow{P_2O_5, \Delta} W$ $\xrightarrow{CH_3MgBr, H_3^+O} X$ $\xrightarrow{Ca(OH)_2, I_2 (\text{yellow ppt.})} Y$ $\xrightarrow{\Delta} Z$
$Z$ is:
$Cyclopentanecarboxamide$ $\xrightarrow{P_2O_5, \Delta} W$ $\xrightarrow{CH_3MgBr, H_3^+O} X$ $\xrightarrow{Ca(OH)_2, I_2 (\text{yellow ppt.})} Y$ $\xrightarrow{\Delta} Z$
$Z$ is:
Which of the following compounds does not give the iodoform test?
Difficult
View Solution$CH_3CH=CHCHO$ is oxidized to $CH_3CH=CHCOOH$ using
Medium
View SolutionCompound $CH_3-CO-CH_2-OH$ reduces:
Medium
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