A student has to answer 10 out of 13 question | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The student must select $10$ questions out of $13$ such that at least $5$ are from the first $6$ questions. This implies two possible cases:Case $

Vedclass · Accepted Answer

$161$

Vedclass · Answer

(C) The student must select $10$ questions out of $13$ such that at least $5$ are from the first $6$ questions. This implies two possible cases:Case $I$: Selecting $5$ questions from the first $6$ and $5$ questions from the remaining $7$.Number of ways $= {}^{6}C_{5} 	imes {}^{7}C_{5} = 6 	imes 21 = 126$.Case $II$: Selecting $6$ questions from the first $6$ and $4$ questions from the remaining $7$.Number of ways $= {}^{6}C_{6} 	imes {}^{7}C_{4} = 1 	imes 35 = 35$.Total number of ways $= 126 + 35 = 161$.

$A$ student has to answer $10$ out of $13$ questions in an examination,choosing at least $5$ questions from the first $6$ questions. The number of choices available to the student is:

Similar Questions

The least value of natural number $n$ satisfying $C(n, 5) + C(n, 6) > C(n + 1, 5)$ is

In a conference of $8$ persons,if each person shakes hands with every other person exactly once,then the total number of handshakes is:

Out of $7$ consonants and $4$ vowels,the number of words consisting of $3$ consonants and $2$ vowels that can be formed is:

There are $7$ identical white balls and $3$ identical black balls. The number of distinguishable arrangements in a row of all the balls,so that no two black balls are adjacent is

$A$ bag contains $5$ black and $6$ red balls. Determine the number of ways in which $2$ black and $3$ red balls can be selected.

Vedclass Test Series

Exam Paper Generator

Online Exam Module