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(A) Given: Relative permeability, $\mu_r = \frac{800}{\pi}$.Current, $I = 2 	ext{ A}$.Number of turns per unit length, $n = 1000 	ext{ m}^{-1}$.The

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$640$

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(A) Given: Relative permeability, $\mu_r = \frac{800}{\pi}$.Current, $I = 2 	ext{ A}$.Number of turns per unit length, $n = 1000 	ext{ m}^{-1}$.The magnetic field intensity $H$ inside the solenoid is given by $H = nI$.$H = 1000 	imes 2 = 2000 	ext{ A/m} = 2 	imes 10^3 	ext{ A/m}$.The magnetic field $B$ is given by $B = \mu H = \mu_0 \mu_r H$.Substituting the values: $B = (4\pi 	imes 10^{-7}) 	imes (\frac{800}{\pi}) 	imes (2 	imes 10^3)$.$B = 4 	imes 10^{-7} 	imes 800 	imes 2 	imes 10^3$.$B = 6400 	imes 10^{-4} 	ext{ T} = 0.64 	ext{ T}$.Since $1 	ext{ T} = 1000 	ext{ mT}$, $B = 0.64 	imes 1000 	ext{ mT} = 640 	ext{ mT}$.

$A$ solenoid has a core of a material with relative permeability $\frac{800}{\pi}$. The windings of the solenoid are insulated from the core and carry a current of $2 \text{ A}$. If the number of turns is $1000 \text{ turns/m}$, find the magnetic field $B$. (in $\text{ mT}$)

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