$\mathop {\lim }\limits_{x \to \pi /2} \tan x \log \sin x = $

  • A
    $0$
  • B
    $1$
  • C
    $-1$
  • D
    इनमें से कोई नहीं

Explore More

Similar Questions

$\mathop {\lim }\limits_{\alpha \to \pi /4} \frac{{\sin \alpha - \cos \alpha }}{{\alpha - \frac{\pi }{4}}} = $

$\lim _{x \rightarrow 0} \frac{2 \sin x-\sin 2 x}{x^3}$ का मान ज्ञात कीजिए।

मान लीजिए $f : R \rightarrow R$ एक अवकलनीय फलन है,इस प्रकार कि $f \left(\frac{\pi}{4}\right)=\sqrt{2}$,$f \left(\frac{\pi}{2}\right)=0$ और $f^{\prime}\left(\frac{\pi}{2}\right)=1$ है। यदि $g(x)=\int\limits_{x}^{\pi / 4}\left(f^{\prime}(t) \sec t+\tan t \sec t f(t)\right) d t$ जहाँ $x \in\left[\frac{\pi}{4}, \frac{\pi}{2}\right)$ है,तो $\lim\limits _{ x \rightarrow\left(\frac{\pi}{2}\right)^{-}} g ( x )$ का मान ज्ञात कीजिए।

सीमा $\mathop {\lim }\limits_{x \to 0} \frac{{{e^x} - {e^{ - x}} - 2x}}{{x - \sin x}}$ का मान है

यदि $f(x)=3 x^{15}-5 x^{10}+7 x^5+50 \cos (x-1)$ है,तो $\lim _{h \rightarrow 0} \frac{f(1-h)-f(1)}{h^3+3 h}=$

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo