A diode and a resistor are connected as shown | vedclass

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Question

(D) diode is forward biased if the potential at the $p$-side (anode) is higher than the potential at the $n$-side (cathode). Otherwise, it is reverse

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Fig. $(1)$ is reverse biased and Fig. $(2)$ is forward biased.

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(D) diode is forward biased if the potential at the $p$-side (anode) is higher than the potential at the $n$-side (cathode). Otherwise, it is reverse biased.In Fig. $(1)$:The $p$-side of diode $D_1$ is at $-5 \ V$ and the $n$-side is connected to $-3 \ V$ through resistor $R_1$. Since $-5 \ V In Fig. $(2)$:The $p$-side of diode $D_2$ is at $0 \ V$ and the $n$-side is connected to $-4 \ V$ through resistor $R_2$. Since $0 \ V > -4 \ V$, the potential at the $p$-side is higher than the potential at the $n$-side. Therefore, diode $D_2$ is forward biased.Thus, Fig. $(1)$ is reverse biased and Fig. $(2)$ is forward biased.

$A$ diode and a resistor are connected as shown in the figure. Out of the following statements, which one is true regarding the biasing of the diodes?

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